\(a)\dfrac{2x-3}{3}-\dfrac{x-3}{6}=\dfrac{4x+3}{5}-17\)
\(\Leftrightarrow\dfrac{10\left(2x-3\right)-5\left(x-3\right)}{30}=\dfrac{6\left(4x+3\right)}{30}-\dfrac{30.17}{30}\)
\(\Leftrightarrow20x-30-5x+15=24x+18-510\)
\(\Leftrightarrow15x-15=24x-492\)
\(\Leftrightarrow15x-15-24x+492=0\)
\(\Leftrightarrow477-9x=0\)
\(\Leftrightarrow x=53\)
\(\text{Vậy phương trình trên có tập nghiệm là S=}\left\{53\right\}\)
\(b)\dfrac{5x-6}{3}-\dfrac{2x+3}{12}-\dfrac{x-1}{4}=1\)
\(\Leftrightarrow\dfrac{4\left(5x-6\right)-\left(2x+3\right)-3\left(x-1\right)}{12}=\dfrac{12}{12}\)
\(\Leftrightarrow20x-24-2x-3-3x+3=12\)
\(\Leftrightarrow15x-24=12\)
\(\Leftrightarrow15x-24-12=0\)
\(\Leftrightarrow15x-36=0\)
\(\Leftrightarrow x=\dfrac{36}{15}=\dfrac{12}{5}\)
\(\text{Vậy phương trình trên có tập nghiệm là S=}\left\{\dfrac{12}{5}\right\}\)
a: \(\dfrac{2x-3}{3}-\dfrac{x-3}{6}=\dfrac{4x+3}{5}-17\)
=>10(2x-3)-5(x-3)=6(4x+3)-510
=>20x-30-5x+15=24x+18-510
=>24x-492=15x-15
=>9x=477
=>x=53
b: \(\dfrac{5x-6}{3}-\dfrac{2x+2}{12}-\dfrac{x-1}{4}=1\)
=>4(5x-6)-2x-2-3(x-1)=12
=>20x-24-2x-2-3x+3=12
=>15x-23=12
=>15x=35
=>x=35/15=7/3
\(a,\dfrac{2x-3}{3}-\dfrac{x-3}{6}=\dfrac{4x+3}{5}-17\)
\(\Rightarrow\dfrac{10\left(2x-3\right)-5\left(x-3\right)-6\left(4x+3\right)-17.30}{30}=0\)
\(\Rightarrow20x-30-5x+15-24x-18-510=0\)
\(\Rightarrow-9x=-477\)
\(\Rightarrow x=53\)
