\(4x^2-4x+3=0\)
\(\Rightarrow4x^2-4x+1+2=0\)
\(\Rightarrow\left(2x-1\right)^2+2=0\)
Vì \(\left(2x-1\right)^2\ge0\forall x\)\(\Rightarrow\left(2x-1\right)^2+2\ge2\)
\(\Rightarrow\left(2x-1\right)^2=0\)( vô lý )
\(\Rightarrow x\in\varnothing\)
\(4x^2-4x+3=0\)
\(\left(2x\right)^2-2.2x.1+1+2=0\)
\(\left(2x-1\right)^2+2=0\)
\(\left(2x-1\right)^2=-2\)
\(\text{Vì }\left(2x-1\right)^2\ge0\forall x\)
\(\text{Mà}\left(2x-1\right)^2=-2\)
\(\Rightarrow\text{Ko có giá trị x thỏa mãn đề bài}\)