Question

giải giúp mk với :

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Answer 1

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Answer 2

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Answer 3

Answer 4

Câu 3:

\(\left\{{}\begin{matrix}\dfrac{1}{x+3}-\dfrac{2}{y-1}=9\\\dfrac{3}{x+3}+\dfrac{1}{y-1}=6\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}\dfrac{3}{x+3}-\dfrac{6}{y-1}=27\\\dfrac{3}{x+3}+\dfrac{1}{y-1}=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-\dfrac{7}{y-1}=21\\\dfrac{3}{x+3}+\dfrac{1}{y-1}=6\end{matrix}\right.\)

=>y-1=-1/3 và 3/x+3=6-1/y-1=6-1:(-1/3)=6+3=9

=>y=2/3 và x+3=1/3

=>x=-8/3; y=2/3