Question

giải giúp mình nha

Answer 1

ĐKXĐ: \(x\ge3\)

\(\sqrt{\left(x-3\right)\left(x+3\right)}-\sqrt{x-3}=0\)

\(\Leftrightarrow\sqrt{x-3}\left(\sqrt{x+3}-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x-3}=0\\\sqrt{x+3}=1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+3=1\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\left(ktm\right)\end{matrix}\right.\)