Ta có :
\(6^{5x+2}=36^{3x-4}\)
\(\Rightarrow6^{5x+2}=\left(6^2\right)^{3x-4}\)
\(\Rightarrow6^{5x+2}=6^{6x-8}\)
=> 5x + 2 = 6x - 8
=> x = 10
Vậy x = 10
Ta có: \(6^{5x+2}=36^{3x-4}\)
\(=>6^{5x+2}=6^{2\left(3x-4\right)}\)
\(=>5x+2=2\left(3x-4\right)\)
\(=>5x+2=6x-8\)
\(=>x-2=8\)
\(=>x=10\)
\(6^{5x+2}=36^{3x-4}\)
\(\Rightarrow6^{5x+2}=6^{2.\left(3x-4\right)}\)
\(\Rightarrow6^{5x+2}=6^{6x-8}\)
\(\Rightarrow5x+2=6x-8\)
\(\Rightarrow2+8=6x-5x\)
\(\Rightarrow x=10\)
Vậy x = 10
