tinh gia tri cua cac bieu thuc sau
\(\frac{20^{5.}5^{10}}{100^5}\)
b)\(\frac{6^3+3.6^2+3^3}{-13}\)
c)\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)l
1) Tinh gia tri cua bieu thuc:
A=\(\frac{\left(1+2+...+100\right)\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{4}-\frac{1}{5}\right)\left(2,4.42-21.4,8\right)}{1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}\)
B=\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}+6^{11}}\)
\(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)Tinh gia tri bieu thuc
giai gium minh nha
\(\dfrac{-4^6.9^5-6^9.120}{-8^4.3^{12}-6^{11}}\)
(4^6.9^5+6^9.120)/(-6^11-8^4.3^12)
4^6.9^5+6^9.120/-8^4.3^12-6^11
$\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}$
\(\frac{7.\left(4^6.9^5+6^9.120\right)}{-8^4.3^{12}-6^{11}}\)= bn?
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)