Các câu hỏi tương tự
Cho \(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\). Tìm x.
\(\frac{X-6}{7}+\frac{X-7}{8}+\frac{X-8}{9}=\frac{X-9}{10}+\frac{X-10}{11}+\frac{X-11}{12}\)
TIM X:\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
\(\frac{x-7}{6}+\frac{x-11}{10}=\frac{x-8}{7}+\frac{x-10}{9}\)
Tìm x : ...
Giúp mình với nhé
Tìm x biết :
\(\frac{x-6}{7}\)+ \(\frac{x-7}{8}\)+ \(\frac{x-8}{9}\)= \(\frac{x-9}{10}\)+ \(\frac{x-10}{11}\)+ \(\frac{x-11}{12}\)
Tìm x biết
a) x+2x+3x+4x+...+100x=-213
b)\(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
c)3(x-2)+2(x-1)=10
d)\(\frac{x+1}{3}=\frac{x-2}{4}\)
e)\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+\frac{x-11}{12}\)
f)\(\frac{x+32}{11}+\frac{x+23}{12}=\frac{x+38}{13}+\frac{x+27}{14}\)
Tìm x biết
\(\frac{x+4}{9}+\frac{x+11}{8}+\frac{x+16}{7}=10-\frac{x+19}{6}\)
Find the value of x such that \(\frac{x-7}{6}+\frac{x-11}{10}=\frac{x-8}{7}+\frac{x-10}{9}\)
.
Answer: .x=..
cho A là nghiệm của phương trình
\(\frac{x-7}{x-8}-\frac{x-8}{x-9}=\frac{x-10}{x-11}-\frac{x-11}{x-12}.\)
Tìm 6A