Cho \(\frac{x}{-2}=\frac{9}{y}=\frac{3-2z}{5};x+z=0.\)Khi đó y=?
cho \(\frac{x}{-2}=\frac{9}{y}=\frac{3-2z}{5};x+z=0\)
khi dod y =.....?
\(\frac{x}{-2}=\frac{9}{y}=\frac{3-2z}{5}vàx+z=0\). Khi đó y=_______
cho x/-2=9/y=3-2z/5 va x+z=0 khi do y=
cho \(\frac{x}{-2}=\frac{9}{y}=\frac{3-2z}{5}\) và x+z=0 tìm y
Cho \(\frac{x}{-2}=\frac{9}{y}=\frac{3-2z}{5}\) và \(x+z=0\). Khi đó y =______
tim x,y,z khi
\(\frac{x}{7}=\frac{y}{3}va\)x-24=y
\(\frac{x}{5}=\frac{y}{7}=\frac{z}{2}\)va y-x=48
\(\frac{x}{2}=\frac{y}{3};\frac{y}{4}=\frac{z}{5}\)va x-y- z=28
\(\frac{x}{3}=\frac{y}{5}=\frac{z}{7}\)va 2x+3-z=-14
cho cac so x,y,z va x+y+z khac 0 thoa man dieu kien
\(\frac{x+2y}{x+2y-z}+\frac{y+2z}{y+2z-x}+\frac{z+2x}{z+2x-+y}\)
tinh gt bieu thuc \(T=\frac{x^2+y^2}{xy}+\frac{y^2+z^2}{yz}+\frac{z^2+x^2}{zx}\)
Cho \(\frac{x}{-2}=\frac{9}{y}=\frac{3-2z}{5}\)v
và x + z = 0. vậy y = .........