\(\frac{\frac{\frac{2}{5}}{4}}{\frac{5}{\frac{25}{50}}}=\frac{\frac{2}{5}:4}{5:\frac{25}{50}}=\frac{\frac{2}{5}.\frac{1}{4}}{5.\frac{50}{25}}=\frac{\left(\frac{1}{10}\right)}{10}=\frac{1}{10}:10=\frac{1}{10}.\frac{1}{10}=\frac{1}{100}\)
Chú ý: dấu gạch ngang viết dài hơn để phân biệt tử số và mẫu số của phân số
\(\frac{\frac{8}{5}:\left(\frac{8}{5}.\frac{5}{4}\right)}{\frac{16}{25}-\frac{1}{25}}+\frac{1:\frac{4}{7}}{\left(\frac{50}{9}-\frac{9}{4}\right).\frac{36}{17}}+0,6.0,5:\frac{2}{5}\)
\(\frac{\frac{\frac{2}{5}}{4}}{\frac{\frac{5}{25}}{50}}=?\)
\(\frac{\frac{\frac{2}{5}}{4}}{\frac{\frac{5}{25}}{50}}=?\)
Tìm x biết :
a)\(\frac{2}{3}x-50\%x-\left(-\frac{4}{5}\right):1\frac{3}{5}=-0,12\)\(+1\frac{3}{25}\)
b)\(\left(-1\frac{1}{6}+\frac{2}{3}-\frac{3}{4}\right):x+\left(-1\frac{11}{12}\right).1\frac{21}{23}=-6\frac{1}{3}\)
c)\(50\%x-\frac{1}{3}x-\left(\frac{-2}{3}\right)^2.\left(-1\frac{1}{8}\right)=-119\frac{3}{4}+120\frac{5}{6}\)
\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{2}\)
\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2\)
\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}\)
\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
a)\(\frac{-5}{7}.\left(\frac{2}{11}+\frac{9}{5}\right)+\left(\frac{-9}{11}+\frac{4}{5}\right).\frac{5}{7}\) b)\(2\frac{2}{5}.\frac{5}{9}+1\frac{4}{9}.\frac{12}{5}-1,8.\frac{10}{3}\)c)\(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{4}{13}-\frac{2}{13}.\frac{-7}{25}\)
\(\frac{\frac{\frac{\frac{\frac{2}{4}}{8}}{5}}{25}}{\frac{25}{\frac{5}{\frac{8}{\frac{4}{2}}}}}=?\)
\(\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(100-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{2}{27}}+\left(1,2.0,5\right):\frac{3}{5}\)
Tính
\(\frac{0,6:\frac{4}{5}.1,25}{0,64-\frac{1}{25}}+\frac{\left(10-\frac{2}{25}\right):\frac{4}{70}}{\left(6\frac{5}{9}-3\frac{1}{4}\right).2\frac{1}{17}}+\frac{6}{5}.\frac{1}{2}:\frac{3}{5}\)
