\(\frac{45.16-17}{45.15+28}=\frac{45.15+45-17}{45.15+28}=\frac{45.15+28}{45.15+28}=1\)
45 × 16 - 17/45 × 15 + 28
= 45 × (15 + 1) - 17/45 × 15 + 28
= 45 × 15 + (45 - 17)/45 × 15 + 28
= 45 × 15 + 28/45 × 15 + 28
= 1
\(\frac{45x16-17}{45x15+28}\) = \(\frac{45x15+45-17}{45x15+28}\) = \(\frac{45x15-28}{45x15+28}\) = 1
=45x(15+1)-17/45x15+28
=45x15+45-17/45x15+28
=45x15+28/45x15+28
=1