\(\frac{2}{3}+2\left(x-1\right)=\frac{4}{5}\)
=> \(2\left(x-1\right)=\frac{4}{5}-\frac{2}{3}\)
=> \(2\left(x-1\right)=\frac{2}{15}\)
=> \(x-1=\frac{1}{15}\)
=> \(x=\frac{16}{15}\)
2/3+2(x+1)=4/5
2(x+1)=4/5-2/3
2(x+1)=2/15
(x+1)=2/15:2
(x+1)=1/15
x=1/15-1
x=-14/15
vậy x=-14/15
Bài làm
\(\frac{2}{3}+2\left(x-1\right)=\frac{4}{5}\Leftrightarrow\frac{2}{3}+2x-2=\frac{4}{5}\)
\(\Leftrightarrow-\frac{4}{3}+2x=\frac{4}{5}\Leftrightarrow2x=\frac{32}{15}\Leftrightarrow x=\frac{16}{15}\)
Bài làm :
Ta có :
\(\frac{2}{3}+2\left(x-1\right)=\frac{4}{5}\)
\(\Leftrightarrow2\left(x-1\right)=\frac{4}{5}-\frac{2}{3}\)
\(\Leftrightarrow2\left(x-1\right)=\frac{2}{15}\)
\(\Leftrightarrow x-1=\frac{2}{15}\div2=\frac{1}{15}\)
\(\Leftrightarrow x=\frac{1}{15}+1=\frac{16}{15}\)
Vậy x=16/15
