Question

\(\frac{1}{4}-\left(x-\frac{5}{8}\right)^{2}=-2\)

Answer 1

(x-5/8)^2= 1/4-(-2)

(x-5/8)^2= 9/4

(x-5/8)^2= (3/2)^2

=> x-5/8= 3/2

x= 3/2+5/8

x= 17/8

chúc e học tốt

Answer 2

Ta có: \(\frac14-\left(x-\frac58\right)^2=-2\)

=>\(\left(x-\frac58\right)^2=\frac14+2=\frac94\)

=>\(\left[\begin{array}{l}x-\frac58=\frac32\\ x-\frac58=-\frac32\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac58+\frac32=\frac58+\frac{12}{8}=\frac{17}{8}\\ x=\frac58-\frac32=\frac58-\frac{12}{8}=-\frac78\end{array}\right.\)

Answer 3

thank Bùi Khánh Huyền

Answer 4

` 1/4 - ( x - 5/8 )^2 = -2`
` ( x - 5/8 )^2 = 1/4 +2`
` ( x - 5/8 )^2 = 1/4 + 8/4`
` ( x - 5/8 )^2 = 9/4`
`( x - 5/8 )^2 = (3/2)^2` hoặc `( x - 5/8 )^2 = (-3/2)^2`
` x - 5/8 = 3/2 ` `x - 5/8 = -3/2`
` x = 3/2 + 5/8 ` ` x = -3/2 + 5/8`
` x = 12/8 + 5/8` ` x = -12 /8 + 5/8`
` x = 17/8` ` x = -7/8 `
Vậy `x`\(\in\) `{17/8; -7/8}`

Answer 5

thank mn