ĐKXĐ: \(x\ne\frac{\pi}{4}+k\pi\)
\(\Leftrightarrow1+2sin^2x-3\sqrt{2}sinx+sin2x=sin2x-1\)
\(\Leftrightarrow2sin^2x-3\sqrt{2}sinx+2=0\)
\(\Leftrightarrow\left[{}\begin{matrix}sinx=\sqrt{2}>1\left(l\right)\\sinx=\frac{\sqrt{2}}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\frac{\pi}{4}+k2\pi\left(l\right)\\x=\frac{3\pi}{4}+k2\pi\end{matrix}\right.\)