\(\frac{-63^{^2}}{13^{^2}}\)+ \(\frac{108^{^2}}{13^{^2}}\)
= \(\frac{-3969}{169}\)+ \(\frac{11664}{169}\)
= \(\frac{-3969+11664}{169}\)
= \(\frac{7695}{169}\)
k mình nha
Mình cảm ơn bạn nhiều
Thank you very much!
(^_^)
\(\frac{-63^{^2}}{13^{^2}}\)+ \(\frac{108^{^2}}{13^{^2}}\)
= \(\frac{-3969}{169}\)+ \(\frac{11664}{169}\)
= \(\frac{-3969+11664}{169}\)
= \(\frac{7695}{169}\)
k mình nha
Mình cảm ơn bạn nhiều
Thank you very much!
(^_^)
tính :
\(\frac{75-\frac{5}{13}+\frac{3}{17}-\frac{3}{19}}{275-\frac{22}{13}+\frac{11}{17}-\frac{11}{19}}\)
2, so sánh
17^ 18 và 63^ 12
tìm x,y thỏa mãn :
( x - \(\sqrt{3}\) )^ 2016 + ( y ^2 -3 ) ^ 2018 = 0
PLEASE , HELP ME
\(\left(\frac{5}{7}-\frac{7}{9}+\frac{9}{11}+\frac{11}{13}+\frac{13}{15}\right).x=5-\frac{2}{7}-\frac{2}{9}-\frac{2}{11}-\frac{2}{13}\)
Tính nhanh
\(\frac{\frac{2}{3}-0.4-\frac{2}{7}+\frac{2}{11}}{\frac{13}{3}-2.6-\frac{13}{7}+\frac{13}{11}}\)
Tính bằng cách hợp lí
a)\(\frac{1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}}{1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}}:\frac{13+\frac{13}{2}+\frac{13}{3}+\frac{13}{4}}{17-\frac{17}{2}+\frac{17}{3}-\frac{17}{4}}\)
\(\frac{\frac{2}{11}+\frac{2}{13}-\frac{2}{19}}{\frac{5}{19}-\frac{5}{11}-\frac{5}{13}}\)
\(\frac{5}{13}.\frac{-2}{3}-\frac{8}{13}.\frac{2}{3}\)
\(\frac{50-\frac{4}{13}+\frac{2}{15}-\frac{2}{17}}{100-\frac{8}{13}+\frac{4}{15}-\frac{4}{17}}\)
các bn làm giúp mk vs thông cảm nha:(đều là hs nên hiểu nhau cả mà,ai làm đc câu nào thì cố giúp mk nha)
a)\(-66\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{11}\right)+124\left(-37\right)+63.\left(-124\right)\)
b)\(\left(2-\frac{3}{2}\right).\left(2-\frac{4}{3}\right).\left(2-\frac{5}{4}\right).\left(2-\frac{6}{5}\right)\)
c)\(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)
d)\(\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{7}+\frac{33}{34}\right]:\left[\left(\frac{7}{2001}+\frac{11}{4002}\right).\frac{2001}{25}+\frac{9}{2}\right]\)
e)\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{2}{7}+\frac{10}{3}\right).\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\frac{1}{3}-\frac{1}{7}-\frac{1}{13}}{\frac{2}{3}-\frac{2}{7}-\frac{2}{13}}.\frac{\frac{1}{3}-0.25+0.2}{1\frac{1}{6}-0.875+0.7}+\frac{6}{7}\)