\(BCNN\left( {6,4} \right) = 12\)
Ta có:
\(\begin{array}{l}12:6 = 2; 12:4 = 3.\\\dfrac{5}{6} = \dfrac{{5.2}}{{6.2}} = \dfrac{{10}}{{12}}\\\dfrac{7}{4} = \dfrac{{7.3}}{{4.3}} = \dfrac{{21}}{{12}}\end{array}\)
BCNN(6,4)=12
Ta có:
\(\dfrac{5}{6}=\dfrac{5.2}{6.2}=\dfrac{10}{12}\)
\(\dfrac{7}{4}=\dfrac{7.3}{4.3}=\dfrac{21}{12}\)