B1:Ta có : \(2\widehat{H}=110^o\)
\(\widehat{H}+\widehat{x}=180^o\) (trong cùng phía)
\(\widehat{x}=180^o-110^o=70^o\)
B2:\(2\widehat{C}=\widehat{130^o}\)
\(\widehat{C}+\widehat{y}=180^o\) (trong cùng phía)
\(\Rightarrow\widehat{y}=180^o-130^o=50^o\)
Ta có : a//b
\(a\perp x\)
\(b\perp x\)
\(\Rightarrow\widehat{x}=90^o\)