Câu hỏi của Thao Buiphuong

Question

Đun nóng 3-methylbutane-2-ol để tách nước thì thu được alkene A (sản phẩm chính). Ozon phân rồi thủy phân A thì thu được 2 sản phẩm B & C. Khử hóa B & C bằng H2 thì thu được ethanol và Propane-2-ol.

Viết các phương trình phản ứng và gọi tên A, B, C.

B.Thị Anh Thơ · Accepted Answer

$CH_3-CHOH-CH\left(CH_3\right)-CH_3\underrightarrow{^{H2SO4,170^oC}}CH_3-CH=C\left(CH_3\right)-CH_3$

$CH_3-CH=C\left(CH_3\right)-CH_3+O_3\rightarrow CH_3-CHOOOC\left(CH_3\right)-CH_3$

$CH_3-COOOC\left(CH_3\right)-CH_3+H_2O\underrightarrow{^{Zn}}CH_3CHO+CH_3COCH_3$

$CH_3CHO+H_2\underrightarrow{^{Ni,t^o}}CH_3CH_2OH$

$CH_3COCH_3+H_2\underrightarrow{^{t^o,Ni}}CH_3CHOHCH_3$

A: 2-methylbut-2-ene

B: acetaldehyde

C: acetoneCâu trả lời: $CH_3-CHOH-CH\left(CH_3\right)-CH_3\underrightarrow{^{H2SO4,170^oC}}CH_3-CH=C\left(CH_3\right)-CH_3$