PTHH: \(C_2H_4+3O_2\underrightarrow{t^o}2CO_2+2H_2O\)
Ta có: \(n_{H_2O}=\frac{3,6}{18}=0,2\left(mol\right)\)
\(\Rightarrow n_{O_2}=0,3mol\) \(\Rightarrow V_{O_2}=0,3\cdot22,4=6,72\left(l\right)\)
\(\Rightarrow V_{kk}=\frac{6,72}{20\%}=33,6\left(l\right)\)