\(n_Y=\frac{1,12}{22,4}=0,5\left(mol\right)\)
Gọi số mol C, S lần lượt là a;b
\(C+O_2\rightarrow CO_2\)
\(S+O_2\rightarrow SO_2\)
Ta có hệ pt:
\(\left\{{}\begin{matrix}12x+32y=12\\x+y=0,5\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,2\left(mol\right)\\y=0,3\left(mol\right)\end{matrix}\right.\)
\(\Rightarrow m_C=0,2.12=2,4\left(g\right)\)
\(\Rightarrow\%m_C=\frac{2,4}{12}.100\%=20\%\)
\(\Rightarrow\%m_S=100\%-20\%=80\%\)
\(\overline{M_Y}=\frac{0,2.44+0,3.64}{0,5}=56\)
\(\Rightarrow d_{Y/H2}=\frac{56}{2}=28\)
