Sửa đề: \(x^2-y^2=-45\)
Đặt \(\dfrac{x}{-2}=\dfrac{y}{3}=k\)
=>\(\left\{{}\begin{matrix}x=-2k\\y=3k\end{matrix}\right.\)
\(x^2-y^2=-45\)
=>\(\left(-2k\right)^2-\left(3k\right)^2=-45\)
=>\(4k^2-9k^2=-45\)
=>\(-5k^2=-45\)
=>\(k^2=9\)
=>\(\left[{}\begin{matrix}k=3\\k=-3\end{matrix}\right.\)
TH1: k=3
=>\(\left\{{}\begin{matrix}x=-2\cdot3=-6\\y=3\cdot3=9\end{matrix}\right.\)
TH2: k=-3
=>\(\left\{{}\begin{matrix}x=-2\cdot\left(-3\right)=6\\y=3\cdot\left(-3\right)=-9\end{matrix}\right.\)