Giải:
\(\dfrac{x-1}{3}-2x+5=\dfrac{2x+3}{4}+1\)
\(\Leftrightarrow\dfrac{x-1}{3}-\dfrac{2x+5}{1}=\dfrac{2x+3}{4}+\dfrac{1}{1}\)
\(\Leftrightarrow\dfrac{4\left(x-1\right)}{3.4}-\dfrac{12\left(2x+5\right)}{12}=\dfrac{3\left(2x+3\right)}{4.3}+\dfrac{12}{12}\)
\(\Leftrightarrow4\left(x-1\right)-12\left(2x+5\right)=3\left(2x+3\right)+12\)
\(\Leftrightarrow4x-4-24x-60=6x+9+12\)
\(\Leftrightarrow4x-24x-6x=9+12+4+60\)
\(\Leftrightarrow-26x=85\)
\(\Leftrightarrow x=\dfrac{85}{-26}=-\dfrac{85}{26}\)
Vậy ...
\(\dfrac{x-1}{3}-2x+5=\dfrac{2x+3}{4}+1\)
\(\Leftrightarrow\)\(\dfrac{4\left(x-1\right)}{12}-\dfrac{24x}{12}+\dfrac{60}{12}=\dfrac{3\left(2x+3\right)}{12}+\dfrac{12}{12}\)
\(\Leftrightarrow\) 4x - 4 - 24x + 60 = 6x + 9 + 12
\(\Leftrightarrow\) -20x + 56 = 6x + 21
\(\Leftrightarrow\) 56 - 21 = 20x + 6x
\(\Leftrightarrow\) 35 = 26x
\(\Leftrightarrow\) x = \(\dfrac{35}{26}\)
Vậy phương trình có no là: S={\(\dfrac{35}{26}\)}
\(\dfrac{x-1}{3}-2x+5=\dfrac{2x+3}{4}+1\)
\(\Leftrightarrow\dfrac{4\left(x-1\right)}{12}-\dfrac{12\left(2x+5\right)}{12}=\dfrac{4\left(2x+3\right)}{12}+\dfrac{12}{12}\)
=>4(x-1)-12(2x+5)=4(2x+3)+12
⇔4x-4-24x-30=8x+12+12
⇔-20x-8x=24+34
⇔-28x=58
=>x=\(\dfrac{-29}{14}\)
ơ.... Phạm Hoàng Giang làm sai sao lại tik cho bn ý....
mấy bn thử thay vào mà xem
