\(=\dfrac{\sqrt{\left(x^2-2\right)^2}}{x^2-2}=\dfrac{\left|x^2-2\right|}{x^2-2}\\ =\left[{}\begin{matrix}\dfrac{x^2-2}{x^2-2}=1,\forall x\ge\sqrt{2}\text{ hoặc }x\le-\sqrt{2}\\\dfrac{2-x^2}{x^2-2}=-1,\forall-\sqrt{2}< x< \sqrt{2}\end{matrix}\right.\)