Question

\(\dfrac{\sqrt{a}+1}{a\sqrt{a}+a+\sqrt{a}}:\dfrac{1}{a^2-\sqrt{a}}\)

rút gọn

Answer 1

`= (sqrt( a + 1))/(sqrta(a + sqrt a+1)) xx (sqrta(sqrta-1)(a + sqrt a + 1))`

`= (sqrt(a+1))/(sqrta(sqrt(a-1))`

Answer 2

đk a > 0

\(=\dfrac{\sqrt{a}+1}{\sqrt{a}\left(a+\sqrt{a}+1\right)}.\dfrac{\sqrt{a}\left(\sqrt{a^3}-1\right)}{1}\\ =\dfrac{\sqrt{a}+1}{a+\sqrt{a}+1}.\dfrac{\left(\sqrt{a}-1\right)\left(a+\sqrt{a}+1\right)}{1}\\ =\left(\sqrt{a}+1\right)\left(\sqrt{a}-1\right)=a-1\)