Question

\(\dfrac{4^{61}-2^{121}}{8^{40}}\)

Answer 1

\(\dfrac{4^{61}-2^{121}}{8^{40}}=\dfrac{2^{122}-2^{121}}{2^{120}}=\dfrac{2^{120}\left(2^2-2\right)}{2^{120}}=2\)

Answer 2

\(\dfrac{4^{61}-2^{121}}{8^{40}}\)

\(=\dfrac{2^{122}-2^{121}}{8^{40}}\)

\(=\dfrac{2^{122}-2^{121}}{2^{120}}\)

\(=\dfrac{\left(2-1\right)2^{121}}{2^{120}}\)

\(=\dfrac{1.2^{121}}{2^{120}}\)

\(=1.2\)

\(=2\)