Question

( \(\dfrac{3}{5}\) )^x + \(\dfrac{98}{125}\) = 1

tìm x

Answer 1

\(\left(\dfrac{3}{5}\right)^x+\dfrac{98}{125}=1\)

\(\left(\dfrac{3}{5}\right)^x=1-\dfrac{98}{125}\)

\(\left(\dfrac{3}{5}\right)^x=\dfrac{27}{125}\)

\(\left(\dfrac{3}{5}\right)^x=\left(\dfrac{3}{5}\right)^3\)

\(\Rightarrow x=3\)

Answer 2

\(\left(\dfrac{3}{5}\right)^x+\dfrac{98}{125}=1\)

           \(\left(\dfrac{3}{5}\right)^x=1-\dfrac{98}{125}\)

           \(\left(\dfrac{3}{5}\right)^x=\dfrac{27}{125}\)

           \(\left(\dfrac{3}{5}\right)^x=\left(\dfrac{3}{5}\right)^3\)

\(\Rightarrow x=3\)

Answer 3

`(3/5)^x - 1 - 98/125`

`(3/5)^x = 27/125`

`x = 3`

Answer 4