Question

cứu tui trời ơi!!

2^(2x+1)-4^(x)=16^(x)

 

Answer 1

\(2^{2x+1}-4^x=16^x\)

\(\Leftrightarrow2^{2x}.2-4^x=\left(4^2\right)^x\)

\(\Leftrightarrow4^x.2-4^x=4^{2x}\)

\(\Leftrightarrow4^x=4^{2x}\)

\(\Leftrightarrow x=2x\)

\(\Leftrightarrow x=0\)

Answer 2

22x+1−4x=16x

\Leftrightarrow2^{2x}.2-4^x=\left(4^2\right)^x⇔22x.2−4x=(42)x

\Leftrightarrow4^x.2-4^x=4^{2x}⇔4x.2−4x=42x

\Leftrightarrow4^x=4^{2x}⇔4x=42x

$\iff x=2x$

$\iff x=0$