Gọi: d = ƯCLN ( 2n + 5; 2n + 4 ) ; \(d\in N\)*
\(\Rightarrow\hept{\begin{cases}2n+5⋮d\\2n+4⋮d\end{cases}\Rightarrow}\left(2n+5\right)-\left(2n+4\right)⋮d\)
\(\Rightarrow1⋮d\)
\(\Rightarrow d=1\)
Vậy: ƯCLN ( 2n + 5; 2n + 4 ) = 1 ( đpcm )
Có 2n+5 luôn luôn lẻ
2n+4 luôn luôn chẵn
Suy ra 2n+5,2n+4 nguyên tố cùng nhau
hay UCLN ( 2n+5,2n+4 )=1(đpcm)