0, ( 37 ) + 0, ( 62 )
= 0 , ( 99 )
\(\approx\)1
Hk tốt
0,(37) + 0,(62) =
\(\frac{37}{99}+\frac{62}{99}=\frac{99}{99}\)
\(\frac{99}{99}=1\)
Bài 1: Tìm x
a, \(\left[0,\left(37\right)+0,\left(62\right)\right].x=10\)
b,\(0,\left(12\right):1,\left(6\right)=x:0,\left(4\right)\)
Bài 1 : Chứng tỏ rằng
a) \(0,\left(37\right)+0,\left(62\right)=1\)
b) \(0,\left(33\right).3=1\)
guip mik nhé đuk tick cho
Thực hiện phép tính sau:
\(B=\frac{5}{9}.2,\left(37\right)+0,\left(5\right).3,\left(62\right)-2\sqrt{\left(\frac{-2}{3}\right)^2}\)
Bài 1:Tính
a)\(0,\left(3\right)+3\frac{1}{3}+0,\left(31\right)\)
b)\(\frac{4}{9}+1,2\left(31\right)-0,\left(13\right)\)
Bài 2:Tìm x,biết
\(0,\left(37\right)\times x=1\)
Thực hiện phép tính:
\(\left(\frac{-31}{37}\right)^5.\left(\frac{37}{62}\right)^5\)
tính
a)\(\left(-\frac{31}{37}\right)^5.\left(\frac{37}{62}\right)\)
b)\(\left(x-\frac{3}{5}\right)^2+|\frac{-7}{23}|+\left(-\frac{4}{25}\right)\)
giúp mình nhé !!!
Lập bảng xét dấu:
\(M=\left(2x-1\right)\left(3+x\right)>0\)
\(N=\left(3-x\right)\left(x+4\right)< 0\)
\(P=\left(4-2x\right)\left(x-1\right)>0\)
Tìm a,b,c biết
a, \(\left(2a+1\right)^2+\left(b+3\right)^4+\left(5c-6\right)^2< =0\)
b,\(\left(a-7\right)^2+\left(3b+2\right)^2+\left(4c-5\right)^6< =0\)
c,\(\left(12a-9\right)^2+\left(8b+1\right)^4+\left(c+19\right)^6< =0\)
d,\(\left(7b-3\right)^4+\left(21a-6\right)^4+\left(18c+5\right)^6< =0\)
\(Bài\) \(2:\) \(Tìm\) \(x:\)
b) \(\left(5-x\right)^3+27=0\)
d) \(\left(x^2-1\right).\left(x+7\right)=0\)
f) \(\left(x^2+81\right).\left(x-7\right).\left(x^2-2\right)=0\)
