Vì \(10!=10.9.8.7.6.5.4.3.2.1\)
\(\Leftrightarrow10!=2.5.9.2^3.7.2.3.5.2^2.3.2.1\)
\(\Leftrightarrow10!=\left(2.2^3.2.2^2.2\right).1.3^2.5^2.7.9\)
\(\Leftrightarrow10!=2^8.3^2.5^2.7.9\)
Vậy \(10!⋮2^8\)
Ta có : 10! = 10.9.8.7.6.5.4.3.2.1
= (2.5)9.23.7.(2.3)5.22.3.2
= (2.23.2.22.2)(5.9.7.3.5.3)
= 28(5.9.7.3.5.3) \(⋮2^8\)
=> đpcm
@Võ Như Quỳnh
\(10!=10.9.8.7.6.5.4.3.2.1\)
\(\Rightarrow10!=2.5.9.2^3.7.2.3.5.2^2.3.2.1\)
\(\Rightarrow10!=2.2^3.2.2^2.2.5.9.7.3.5.3.1\)
\(\Rightarrow10!=2^{1+3+1+2+1}.5.9.7.3.5.3.1\)
\(\Rightarrow10!=2^8.5.8.7.3.5.3.1\)
Có \(2^8⋮2^8\)
\(\Rightarrow10!⋮2^8\) \(\left(đpcm\right)\)
Vì 10 ! = 10.9.8.7.6.5.4.3.2.1 \(\Leftrightarrow\) 10 ! = 2.5.9.23.7.2.3.5.22.3.2.1 \(\Leftrightarrow\) 10 ! = ( 2.23.2.22.2 ) . 1.32.52.7.9 \(\Leftrightarrow\) 10 ! = 28.32.52.7.9 Vậy 10 ! \(⋮\) 28
\(10!= 10.9.8.7.6.5.4.3.2.1\)
Có \(8⋮8\)
\(\Rightarrow10!⋮8\left(ĐPCM\right)\)