\(\frac{16}{x}+\frac{1}{4y}=\frac{4^2}{x}+\frac{\left(\frac{1}{2}\right)^2}{y}\ge\frac{\left(4+\frac{1}{2}\right)^2}{x+y}=\frac{81}{20}\)
\(P_{min}=\frac{81}{20}\) khi \(\left\{{}\begin{matrix}x+y=5\\\frac{x}{4}=2y\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=\frac{40}{9}\\y=\frac{5}{9}\end{matrix}\right.\)