a: sin C=AB/BC=3/5
cos C=4/5
tan C=3/4
cot C=4/3
b: \(AH=\dfrac{9\cdot12}{15}=\dfrac{108}{15}=7.2\left(cm\right)\)
\(BH=\dfrac{AB^2}{BC}=\dfrac{81}{15}=5.4\left(cm\right)\)
CH=15-5,4=9,6(cm)
c: \(AI\cdot AB=AH^2\)
\(AK\cdot AC=AH^2\)
Do đó: \(AI\cdot AB=AK\cdot AC\)