Tam giác ABC vuông ở A, ta có:
\(\cos B=\frac{AB}{BC}\); \(\cos C=\frac{AC}{BC}\).
Vậy \(\frac{\cos B}{\cos C}=\frac{AB}{BC}:\frac{AC}{BC}=\frac{AB}{BC}.\frac{BC}{AC}=\frac{AB}{AC}\).
Ta có: \(\cos B=\frac{AB}{AC}\)
\(\cos C=\frac{AC}{BC}\)
\(\Rightarrow\frac{\cos B}{\cos C}=\frac{\frac{AB}{BC}}{\frac{AC}{BC}}=\frac{AB}{BC}.\frac{BC}{AC}=\frac{AC}{BC}\left(đpcm\right)\)
\(\Rightarrow\frac{AB}{AC}=\frac{\cos B}{\cos C}\)