(vẽ tam giác ABC vuông tại A)
Ta có: \(\cos B=\dfrac{AB}{BC}\)
\(\cos C=\dfrac{AC}{BC}\)
\(\Rightarrow\dfrac{\cos B}{\cos C}=\dfrac{\dfrac{AB}{BC}}{\dfrac{AC}{BC}}=\dfrac{AB}{BC}.\dfrac{BC}{AC}=\dfrac{AB}{AC}\left(đpcm\right)\)
Vậy \(\dfrac{AB}{AC}=\dfrac{\cos B}{\cos C}\)