a) Ta có:
\(AC=AD+CD.\\ \Rightarrow12=AD+3.\\ \Rightarrow AD=9\left(cm\right).\)
Xét \(\Delta ABC:DE//BC\left(gt\right). \)
\(\Rightarrow\dfrac{DE}{BC}=\dfrac{AD}{AC}=\dfrac{AE}{AB}.\) (Hệ quả định lí Ta-lét).
\(\Rightarrow\dfrac{DE}{20}=\dfrac{9}{12}=\dfrac{12}{AB}.\)
\(\Rightarrow DE=15\left(cm\right);AB=16\left(cm\right).\)
Xét \(\Delta ADE\) và \(\Delta ACB:\)
\(\dfrac{AD}{AC}=\dfrac{AE}{AB}\left(cmt\right).\\ \widehat{A}chung.\\ \Rightarrow\Delta ADE\sim\Delta ACB\left(c-g-c\right).\)