Theo hệ thức Vi-et ta có \(\left\{{}\begin{matrix}x_1+x_2=-a\\x_1x_2=b\end{matrix}\right.\)
\(\Rightarrow5a+b=22\)
\(\Leftrightarrow x_1x_2-5\left(x_1+x_2\right)=22\)
\(\Leftrightarrow\left(x_1-5\right)\left(x_2-5\right)=47\)
Vì x1,x2 là số nguyên dương nên
\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x_1-5=1\\x_2-5=47\end{matrix}\right.\\\left\{{}\begin{matrix}x_1-5=47\\x_2-5=1\end{matrix}\right.\end{matrix}\right.\)=>.....