2H2S+SO2−−−>2H2O+2S
Ta có
n S=96/32=3(mol)
Theo pthh
n H2S=n S=3(mol)
V H2S=3.22,4=67,2(l)
n SO2=1/2n S=1,5(mol)
V SO2=1,5.22,4=33,6(l)
a) 2H2S + SO2 \(\rightarrow\) 2H2O + 3S\(\downarrow\)
b)- nS = 3
- theo phương trình => nH2S = 2/3nS=2 ; nSO2 = 1/3 nS=1
=> VH2S=44.8l ; VSO2 = 22.4l