Theo bà ra ta có :
\(f\left(2\sqrt{3}\right)=\left(m+1\right)x-2=\left(m+1\right)\left(2\sqrt{3}\right)-2\)
\(=\sqrt{12}\left(m+1\right)-2\)
\(f\left(3\sqrt{2}\right)=\left(m+1\right)x-2=\left(m+1\right)3\sqrt{2}-2\)
\(=\sqrt{18}\left(m+1\right)-2\)
vì 12 < 18 => \(\sqrt{12}< \sqrt{18}\)
hay \(f\left(2\sqrt{3}\right)< f\left(3\sqrt{2}\right)\)