Đặt \(\frac{a}{b}=\frac{c}{d}=k\)\(\Rightarrow a=bk;c=dk.\)
\(\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7b^2k+3bkb}{11b^2k-8b^2}=\frac{\left(7+3\right).b^2k}{ \left(11k-8\right).b^2}=k\)
=\(\frac{7c^2+3cd}{11c^2-8d^2}=\frac{7d^2k+3dkd}{11d^2k-8d^2}=\frac{\left(7+3\right).d^2k}{\left(11k-8\right).d^2}=k\)
Cho \(\frac{a}{b}=\frac{c}{d}.CMR:\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
CMR nếu a/b=c/d thì\(\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
cho \(\frac{a}{b}=\frac{c}{d}.chứngminhrằng:\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2+8d^2}\)
cho a/b= c/d thì
chứng minh\(\frac{7a^2-3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
CMR nếu a/c =b/d thì:
\(\frac{7a^2+3ab}{11a^2+8b^2}=\frac{7c^2+3cd}{11c^2+8d^2}\)
cho ti le thuc \(\frac{a}{b}=\frac{c}{d}\) CMR: \(\frac{7a^2-3ab}{11a^2-8b^2}=\frac{7c^2-3cd}{11c^2-8d^2}\)
\(\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
cho \(\frac{a}{b}=\frac{c}{d}\)Chứng minh
C/m : nếu a/b = c/d thì
\(\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
Cho tỉ số \(\frac{a}{b}=\frac{c}{d}\) .CM
\(\frac{7a^2+3ab}{11a^2-8b^2}=\frac{7c^2+3cd}{11c^2-8d^2}\)
