Ta có: \(\frac{2a+b}{a-b}=\frac{2c+d}{c-d}.\)
\(\Rightarrow\left(2a+b\right).\left(c-d\right)=\left(2c+d\right).\left(a-b\right)\)
\(\Rightarrow2a.\left(c-d\right)+b.\left(c-d\right)=2c.\left(a-b\right)+d.\left(a-b\right)\)
\(\Rightarrow2ac-2ad+bc-bd=2ac-2bc+ad-bd\)
\(\Rightarrow2ad+bc-bd=2bc+ad-bd\)
\(\Rightarrow2ad+bc=2bc+ad.\)
\(\Rightarrow2ad-ad=2bc-bc\)
\(\Rightarrow ad=bc\)
\(\Rightarrow\frac{a}{b}=\frac{c}{d}\left(đpcm\right).\)
Chúc em học tốt!