Lời giải:
\(\frac{1}{a}+\frac{1}{b}=1\Rightarrow a+b=ab\)
Khi đó:
\(A=\frac{(a^2-b^2)^2}{a^4b^4}+\frac{4}{ab}=\frac{(a-b)^2(a+b)^2}{(ab)^4}+\frac{4}{ab}\)
\(=\frac{(a-b)^2(ab)^2}{(ab)^4}+\frac{4}{ab}=\frac{(a-b)^2}{(ab)^2}+\frac{4ab}{(ab)^2}=\frac{(a-b)^2+4ab}{(ab)^2}=\frac{(a+b)^2}{(ab)^2}=\frac{(ab)^2}{(ab)^2}=1\)
Vậy.........