Question

cho A=abc+ab+1997

      B=1ab9+9ac+9b

      so sánh A và B

Answer 1

A = \(\overline{abc}+\overline{ab}+1997\)

B = \(\overline{1ab9}\) + \(\overline{9ac}\) + \(\overline{9b}\)

B = 1009 + \(\overline{ab0}\) + 900 + \(\overline{a0}\)+ c+ 90 + b

B = 1999 + \(\overline{abc}\) + \(\overline{ab}\) > \(\overline{abc}+\overline{ab}+1997\) = A

Vậy B > A