Ta có : A = ( 1 + 4 ) + ( 42 + 43 ) + (44 + 45) + (46+ 47) + 48
= 5 + 42. ( 1 + 4) +44.(1 + 4) + 46 . ( 1 + 4) + 48
= 5( 1 + 42 + 44 + 46) + 48
=> A không chia hết cho 5
\(A=\left(1+4+4^2\right)+\left(4^3+4^4+4^5\right)+\left(4^6+4^7+4^8\right)\)
\(=1.21+4^3.\left(1+4+4^2\right)+4^6.\left(1+4+4^2\right)\)
\(=3.7.\left(1+4^3+4^6\right)\)
=> \(A⋮7\)