a)Từ \(5x=3y\Rightarrow\frac{x}{3}=\frac{y}{5}\Leftrightarrow\frac{2x}{10}=\frac{3y}{15}\)
Áp dụng tc dãy tỉ
\(\frac{2x}{10}=\frac{3y}{15}=\frac{2x-3y}{10-15}=\frac{8}{-5}\)
\(\Rightarrow\frac{2x}{10}=-\frac{8}{5}\Rightarrow x=-8\)
a)
\(\begin{cases}5x=3y\\2x-3y=8\end{cases}\)\(\Rightarrow2x-5x=8\)\(\Rightarrow x=-\frac{8}{3}\)
Vậy x = - 8 / 3
b)
\(\begin{cases}5x=3y\\3x+2y=-15\end{cases}\)\(\Rightarrow\begin{cases}10x=6y\\9x+6y=-45\end{cases}\)
\(\Rightarrow9x+10x=-45\)
\(\Rightarrow x=-\frac{45}{19}\)
Vậy x = - 45 / 19
b)Từ \(5x=3y\Rightarrow\frac{x}{3}=\frac{y}{5}\Rightarrow\frac{3x}{9}=\frac{2y}{10}\)
Áp dụng tc dãy tỉ
\(\frac{3x}{9}=\frac{2y}{10}=\frac{3x+2y}{9+10}=\frac{-15}{19}\)
\(\Rightarrow\frac{3x}{9}=-\frac{15}{19}\Rightarrow x=-\frac{45}{19}\)
a)Từ \(5x=3y\Rightarrow\frac{x}{3}=\frac{y}{5}\Leftrightarrow\frac{2x}{6}=\frac{3y}{15}\)
Áp dụng tc dãy tỉ
\(\frac{2x}{6}=\frac{3y}{15}=\frac{2x-3y}{6-15}=\frac{8}{-9}\)
\(\Rightarrow\frac{2x}{6}=\frac{-8}{9}\Rightarrow x=-\frac{8}{3}\)