Áp dụng TC DTSBN ta có :
\(k=\frac{\left(b+c+d\right)+\left(a+c+d\right)+\left(d+a+b\right)+\left(a+b+c\right)}{a+b+c}=\frac{3a+3b+3a+3d}{a+b+c}=\frac{3\left(a+b+c+d\right)}{a+b+c+d}=3\)
Vậy \(k=3\)
Áp dụng TC DTSBN ta có :
\(k=\frac{\left(b+c+d\right)+\left(a+c+d\right)+\left(d+a+b\right)+\left(a+b+c\right)}{a+b+c}=\frac{3a+3b+3a+3d}{a+b+c}=\frac{3\left(a+b+c+d\right)}{a+b+c+d}=3\)
Vậy \(k=3\)
Cho a, b, c, d la cac so nguyen duong thoa man a + b=c + d= 25
Tim GTLN cua M = \(\frac{c}{b}\)+ \(\frac{d}{a}\)
cho 4 số a,b,c sao cho a+b+c khác 0
biết b+c+d/a=c+d+a/b=d+a+b/c=a+b+c/d=K
Tim K
bai1 cho a/b=c/d voi a,b,c,d la nhung so tu nhien khác 0 CMR (a,d)/(b,c)=[b,c]/[a,d]
Cho cac so a,b,c,d thoa man: \(\frac{a}{b+c+d}=\frac{b}{c+d+a}=\frac{c}{d+a+b}=\)
\(\frac{d}{a+b+c}\). Tinh gia tri bieu thuc:
P=\(\frac{a+b}{c+d}=\frac{b+c}{d+a}=\frac{c+d}{b+a}=\frac{d+a}{b+c}\)
Cho a, b, c, d la cac so nguyen duong thoa man a2+b2=b2+d2. CM a+b+c+d la hop so
cho a,b,c,d la 4 so khac 0 thoa man b^2 =ac va c^2=bd.Cmr\(\frac{a^3+b^3+c^3}{b^3+c^3+d^3}\)=\(\frac{a}{b}\)
Cho 4 số a;b;c;d sao cho a+b+c+d khác 0.Biết (b+c+d)/a=(c+d+a)/b=(d+a+b)/c=(a+b+c)/d=k Tính k
cho a,b,c,d sao cho a+b+c+d ko bang 0
va \(\frac{a+b+c}{d}\)= \(\frac{b+c+d}{a}\)=\(\frac{c+d+a}{b}\)= \(\frac{d+a+b}{c}\)= k
tim k
Cho cac so a,b,c,d thoa man a+b=67,c+d=30 tinh gia tri bieu thuc P=ad+bc+ac+bd