Ta có: \(\left\{{}\begin{matrix}m_{Al}=3,27.41,28\%=1,35\left(g\right)\\m_{Mg}=3,27-1,35=1,92\left(g\right)\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}n_{Al}=\dfrac{1,35}{27}=0,05\left(mol\right)\\n_{Mg}=\dfrac{1,92}{24}=0,08\left(mol\right)\end{matrix}\right.\)
PTHH:
\(4Al+3O_2\xrightarrow[]{t^o}2Al_2O_3\)
0,05->0,0375
\(2Mg+O_2\xrightarrow[]{t^o}2MgO\)
0,08->0,04
=> V = (0,04 + 0,0375).22,4 = 1,736 (l)