2RCOOH + Na2CO3→2RCOONa + H2O + CO2
\(\frac{20,15}{M_R+45}\) ------------------>\(\frac{20,15}{M_R+45}\)------------->\(\frac{20,15}{2\left(M_R+45\right)}\)
Mà theo đề bài có: \(n_{RCOONa}=\frac{28,95}{M_R+67}\)
=>\(\frac{20,15}{M_R+45}=\frac{28,95}{M_R+67}\)
=>\(M_R=5,375=>n_{CO_2}=\frac{20,15}{2\left(5,375+45\right)}=0,2\left(mol\right)\)
=>\(V_{CO_2}=0,2.22,4=4,48\left(l\right)\)
2RCOOH + Na2CO3 \(\rightarrow\)2RCOONa + CO2 + H2O
2(R+45)______________2(R+67)
20.15_________________28.95
<=> 28.95*2 (R+45)=20.15*2(R+67)
<=> R= 43/8
nCO2= 20.15/2(R+45)= 20.15/2(43/8+45)= 0.2 mol
VCO2= 0.2*22.4=4.48l