Mg + 2HCl -> MgCl2 + H2 (1)
2Al + 6HCl -> 2AlCl3 + 3H2 (2)
Zn + 2HCl -> ZnCl2 + H2 (3)
nH2=13,352/22,4=0,6(mol)
Đặt nMg=a\(\Leftrightarrow\)24a
nAl=b\(\Leftrightarrow\)27b
nZn=c\(\Leftrightarrow\)65c
Ta có hệ:
\(\left\{{}\begin{matrix}24a+27b+65c=19,46\\a+\dfrac{3}{2}b+c=0,6\\24a=27b\end{matrix}\right.\)
=>a=?;b=?;c=?
Tiếp tục nhé