a)
PTHH:
\(CuO+H_2SO_4\rightarrow CuSO_4+H_2O\)
\(Cu+2H_2SO_{4\left(đ,n\right)}\rightarrow CuSO_4+SO_2+2H_2O\)
b) \(n_{SO_2}=\dfrac{1,12}{22,4}=0,05\left(mol\right)\)
PTHH: \(Cu+2H_2SO_{4\left(đ,n\right)}\rightarrow CuSO_4+SO_2+2H_2O\)
0,05<---------------------------0,05
=> \(\%m_{Cu}=\dfrac{0,05.64}{10}.100\%=32\%\Rightarrow\%m_{CuO}=100\%-32\%=68\%\)
a)
\(CuO+H_2SO_{4\left(loãng\right)}\rightarrow CuSO_4+H_2O\\ Cu+2H_2SO_{4\left(đặc,nóng\right)}\rightarrow CuSO_4+SO_2+2H_2O\)
b)
\(n_{Cu}=n_{SO_2}=\dfrac{1,12}{22,4}=0,05\left(mol\right)\\ \Rightarrow\left\{{}\begin{matrix}\%m_{Cu}=\dfrac{0,05.64}{10}.100\%=32\%\\\%m_{CuO}=100\%-32\%=68\%\end{matrix}\right.\)