Gọi %1H = x%
Ta có: \(\overline{A}=\dfrac{1.x+2\left(100-x\right)}{100}=1,008\)
=> x = 99,2
\(n_{CH_4}=\dfrac{3,36}{22,4}=0,15\left(mol\right)\Rightarrow n_H=0,15.4=0,6\left(mol\right)\)
=> \(n_{^1H}=0,6.99,2\%=0,5952\left(mol\right)\)
=> Số nguyên tử 1H là 0,5952.6.1023 = 3,5712.1023 (nguyên tử)