\(7^x+7^{x+1}+7^{x+2}=3\cdot19\cdot343\)
=>\(7^x+7^x\cdot7+49\cdot7^x=3\cdot19\cdot343\)
=>\(7^x\left(1+7+49\right)=57\cdot343\)
=>\(7^x=343=7^3\)
=>x=3
`7^x + 7^(x+1) + 7^(x+2) = 3 xx 19 xx 343`
`=> 7^x + 7^x . 7+ 7^x . 7^2 = 19551`
`=> 7^x (1+ 7+ 7^2 )= 19551`
`=> 7^x . 57= 19551`
`=> 7^x = 19551 : 57`
`=> 7^x = 343`
`=> 7^x = 7^3`
`=> x = 3`
Vậy `x= 3`